Find the positive value for which the graph of e x intersects with the graph of Γ(x+1).
(Find the positive value of x which e x = Γ ( x + 1 ) ).
Hint: Γ ( x + 1 ) = x !
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Ah I think I see the confusion. This graph is kind of mislead. x ! should looks like this .
x ! is only defined for whole numbers. For any other numbers, classical gamma function is assumed but not necessary.
Plot [ e y + 5 . 2 9 0 3 1 6 0 9 3 1 1 9 7 7 1 2 4 5 7 6 7 4 2 4 2 6 1 4 3 0 2 7 8 4 2 0 4 4 8 3 0 3 2 2 2 6 5 6 2 − ( y + 5 . 2 9 0 3 1 6 0 9 3 1 1 9 7 7 1 2 4 5 7 6 7 4 2 4 2 6 1 4 3 0 2 7 8 4 2 0 4 4 8 3 0 3 2 2 2 6 5 6 2 ) ! , { y , − 1 0 0 0 0 0 0 1 , 1 0 0 0 0 0 0 1 } ]
Plot [ e x − x ! , { x , 0 , 5 . 3 } ]
I offer my apologies! This problem fooled me -- I did not look far enough out.
I did not believe that there is a closed form solution. A closed form solution was not requested! I found the answer by first doing some plots and then doing a root search in the vicinity of 5.3 where the plots indicated that there might be a solution in positive x .
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x≈5.29