Into the Pyramid

Geometry Level 3

The diagram above shows a triangular pyramid with equal edges and faces, and A , B , C , D A, B, C, D are its vertices.

Let E E be the midpoint of A B AB , O O be the center of the equilateral triangle base, and P P be the center of the 3-D pyramid.

What are the ratios of C O : O E CO : OE and D P : P O DP : PO respectively?

2 : 1 , 4 : 1 2:1 \quad,\quad 4:1 2 : 1 , 2 : 1 2:1 \quad,\quad 2:1 3 : 1 , 2 : 1 3:1 \quad,\quad 2:1 2 : 1 , 3 : 1 2:1 \quad,\quad 3:1 3 : 1 , 4 : 1 3:1 \quad,\quad 4:1 3 : 1 , 3 : 1 3:1 \quad,\quad 3:1

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1 solution

Eggz D
Jun 25, 2020

C O : O E = x : x × s i n 30 \overline{CO} : \overline{OE} = x : x\times sin30 as shown by the 30 degree triangle created below:

D P : P O \overline{DP} : \overline{PO} can be solved in the same way but i prefer this method:

P is the Center of Mass

The Volume of a Prism is A r e a × h e i g h t Area \times height ; the Pyramid's Volume is A r e a × h e i g h t 3 \frac{Area \times height}{3}

The Mass is directly related to the height of the Pyramid, we can derive that the Center of Mass is 1 : 3 1 : 3 up it's height.

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