Intuition

Geometry Level 2

You can create a closed curve of length l l by drawing any path of length l l that connects to its start. Some examples are given above.

Let the maximum area for a closed curve of length 1 be A A . Find 1000 A \lfloor1000A\rfloor .

Clarification: the symbol x \lfloor x \rfloor denotes the largest integer less than or equal to x x .


The answer is 79.

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2 solutions

Our intuition would tell us that the curve with maximum area will be a circle, and this is in fact correct. A circle of circumference 1 1 has radius r = 1 2 π , r = \dfrac{1}{2\pi}, and thus an area of A = π r 2 = 1 4 π . A = \pi r^{2} = \dfrac{1}{4\pi}.

This gives us a final answer of 1000 A = 250 π = 79 . \lfloor 1000A \rfloor = \lfloor \dfrac{250}{\pi} \rfloor = \boxed{79}.

This concept is known as the isoperimetric inequality , two proofs of which are provided in the link.

Great! An intuitive way of explaining why it must be a circle is to imagine filling a 2D rope with a 2D gas. We know it will fill up until it reaches a point where it cannot expand anymore, which is a circle.

Dylan Pentland - 6 years ago

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I like that idea! The same intuition holds in "proving" that a sphere encloses the largest volume among all closed surfaces of a given area.

Brian Charlesworth - 6 years ago

Nice argument (+1)

Raghav Vaidyanathan - 6 years ago

That's really cool. I immediately figured it would be a circle but could not explain why in a simple way. That a very cool way to think about it.

William Derksen - 6 years ago

It should have accepted 79 or 80 based on rounding.

Larry Davidson - 6 years ago

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The . . . \lfloor ... \rfloor symbol indicates the floor function , (aka greatest integer function), which returns the greatest integer less than or equal to the "enclosed" quantity. Then 250 π = 79.57747... = 79. \lfloor \dfrac{250}{\pi} \rfloor = \lfloor 79.57747... \rfloor = 79.

Brian Charlesworth - 6 years ago

Curve with maximum area should be circle (intuition). As length is 1, therefore we can write circumference is 1

Radius r = 1 2 π , r = \dfrac{1}{2\pi}, thus area A = π r 2 = 1 4 π . A = \pi r^{2} = \dfrac{1}{4\pi}.

So [1000A] = [ 250 π \dfrac{250}{\pi} ]= 79

How does it possible the answer be in integral form when an integer is divided or multiplied by an irrational number? The answer is approximately 79.6, then why was it not taken as 80?

Amjad Ali - 6 years ago

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