Inverse Trigo Problem...

Geometry Level 4

The exhaustive set of values of x x , if 2 tan 1 3 x = sin 1 ( 6 x 1 + 9 x 2 ) 2\tan^{-1}3x=\sin^{-1}\left(\dfrac{6x}{1+9x^{2}}\right)

Also see Quadratics

( , 1 3 ) (-\infty,\frac{-1}{3}) [ 1 2 , 6 ] [\frac{1}{2},6] ( , 1 ) (-\infty,-1) ( 2 , ) (2,\infty) [ 2 , 6 ] [2,6] [ 1 3 , 1 3 ] [\frac{-1}{3},\frac{1}{3}]

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