The answer is simply 25, right?

Algebra Level 3

Suppose that x x and y y are inversely proportional and are positive quantities. By what percent does y y decrease if x x is increased by 25 % 25 \% ?


The answer is 20.

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2 solutions

Aditya Paul
May 12, 2015

Take x=K/y, where K is the const. of proportionality. So xy=K.

x(1+25/100)*y(1-d/100)=K. where d is percentage decrease.

(1+25/100)*(1-d/100)=1. dividing both sides by K

Solve it to get d=20, which is the answer.

Feathery Studio
May 8, 2015

If x and y are inversely proportional, we can set up an equation like

y = n x y=\frac{n}{x}

When x x is increased by 25%, we now have the equation

y m = n 1.25 x y-m=\frac{n}{1.25x}

Our expression for percent difference can go as:

y ( y m ) y = m y \frac{y-(y-m)}{y} = \frac{m}{y}

We can replace the variables with the expressions we identified earlier.

We start off with our raw expression for finding the percent decrease.

( n x n 1.25 x ) ( n x ) \frac{(\frac{n}{x}-\frac{n}{1.25x})}{(\frac{n}{x})}

We give both fractions of the numerator a common denominator of 1.25 x 1.25x and combine like terms such that it becomes

( 0.25 n 1.25 x ) ( n x ) \frac{(\frac{0.25n}{1.25x})}{(\frac{n}{x})}

= ( 0.25 n 1.25 x ) ( x n ) =(\frac{0.25n}{1.25x})(\frac{x}{n})

= 0.25 1.25 = 0.2 = 20 =\frac{0.25}{1.25} = 0.2 = 20 %

The percent decrease is 20 \boxed{20} .

Moderator note:

There's a simpler solution for this. Hint: If x x is increased by 25 % 25\% , then x new = x 1.25 x_{\text{new}} = x \cdot 1.25 , what can we say about y new y_{\text{new}} ?

Oh, yes! Since we multiply both sides by 1 1.25 \frac{1}{1.25} , then y 1.25 = 0.8 y \frac{y}{1.25} = 0.8y . The percent difference is y 0.8 y y = 0.2 = 20 100 \frac{y-0.8y}{y} = 0.2 = \frac{20}{100} , or 20%.

Feathery Studio - 6 years ago

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