Ions.

Chemistry Level 1

Find a correct ion expression.

F + \ce { F } ^ { + } . B 3 + \ce { B } ^ { 3+ } . K \ce { K } ^ { - } . S i 3 \ce { Si } ^ { 3- } . N e 2 \ce { Ne } ^ { 2- } . M g 2 \ce { Mg } ^ { 2- } . S 2 + \ce { S } ^ { 2+ } . B e + \ce { Be } ^ { + } .

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1 solution

. .
Mar 16, 2021

Neon, a symbol with N e \ce { Ne } , is an 18th group element, called noble gas, so it cannot be an ion. (Exactly, it can be an ion, but we cannot find it.)

Silicon, a symbol with S i \ce { Si } , is 14th group, so it is ± 4 \pm 4 electrons changes.

Boron, a symbol with B \ce { B } , is 3th group, so it is 3 + 3+ electrons changes.

Potassium, a symbol with K \ce { K } , is 1th group, so it is 1 + 1+ electron changes.

Beryllium, a symbol with B e \ce { Be } , is 2th group, so it is 2 + 2+ electrons changes.

Sulfur, a symbol with S \ce { S } , is 16th group, so it is 2 2- electrons changes.

Magnesium, a symbol with M g \ce { Mg } , is 2th group, so it is 2 + 2+ electrons changes.

Fluorine, a symbol with F \ce { F } , is 17th group, so it is 1 1- electron changes.

The end.

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