Readjust sides to Readjust Area

Geometry Level 4

Let a a and b b be positive integers less than 100.

If the length of a certain rectangle is increased by a % a\% , and the width of the same rectangle is decreased by b % b\% , then the resultant area is increased by 20.17 % 20.17\% .

Find a + b a+b .


The answer is 136.

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1 solution

Saya Suka
Dec 11, 2016

An increase of 20.17 % 20.17\% means that the total area is now 100 % + 20.17 % = 120.17 % = 1.2017 100\%+20.17\%=120.17\%=1.2017 of the original rectangle.

12017 is a product of 2 primes , namely 12017 = 61 × 197 12017=61\times197 .

As we are told that a a and b b are both positive integers less than 100, then 12017 = ( 100 + a ) ( 100 b ) = ( 197 ) ( 61 ) 12017 = (100+a)(100-b) = (197)(61) . Thus a = 197 100 = 97 a=197-100=97 and b = 100 61 = 39 b=100-61=39 . The answer is a + b = 97 + 39 = 136 a+b=97+39=\boxed{136} .

This should be a number theory question

Anupam Nayak - 4 years, 6 months ago

This is definitely crossing into number theory territory, but since the base is geometry it's fine as a geometry topic. We have many problems that fit into more than one category.

Jason Dyer Staff - 4 years, 5 months ago

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