Is Anamul a superhero?

Classical Mechanics Level 4

A truck weighing $10$ Tons carrying $30$ Tons of Atom Bombs was running with the velocity of $35$ m/s. Superhero Anamul rushed to the spot and stopped the Truck at once. His weight is $0.1$ Ton and the force he applied was equal to the friction between his shoe and the road. If the coefficients of static and kinetic friction are equal to the value $1.00$ , then does Superhero Anamul's Heroic work support the principles of Physics?

Hint- Just find out the distance travelled by the truck after Anamul applied the force to stop that. If it does stop at once, obviously Anamul is a Superhero!

The answer is 25000.

1 solution

Anamul Babu
Oct 31, 2015

The force Anamul Applied-

$F= μ_{s} R = μ_{s}mg = 1 \times 100 \times 9.8 = 980 N$

The acceleration gained by the truck

$a = F/M = 980/(30000+10000) = 0.0245 m/s$

The distance travelled by the car

$s = v^{2} / 2a = 35^{2} / (2 \times 0.0245) = 25000m$

So the car didn't actually stopped at once and Anamul is not a superhero! :-( :-( :-(

Is Anamul a superhero?

The answer is 25000.

1 solution

F = μ s R = μ s m g = 1 × 100 × 9.8 = 980 N F= μ_{s} R = μ_{s}mg = 1 \times 100 \times 9.8 = 980 N F = μ s ​ R = μ s ​ m g = 1 × 1 0 0 × 9 . 8 = 9 8 0 N

The acceleration gained by the truck

a = F / M = 980 / ( 30000 + 10000 ) = 0.0245 m / s a = F/M = 980/(30000+10000) = 0.0245 m/s a = F / M = 9 8 0 / ( 3 0 0 0 0 + 1 0 0 0 0 ) = 0 . 0 2 4 5 m / s

The distance travelled by the car

s = v 2 / 2 a = 3 5 2 / ( 2 × 0.0245 ) = 25000 m s = v^{2} / 2a = 35^{2} / (2 \times 0.0245) = 25000m s = v 2 / 2 a = 3 5 2 / ( 2 × 0 . 0 2 4 5 ) = 2 5 0 0 0 m

0 pending reports

$F= μ_{s} R = μ_{s}mg = 1 \times 100 \times 9.8 = 980 N$

$a = F/M = 980/(30000+10000) = 0.0245 m/s$

$s = v^{2} / 2a = 35^{2} / (2 \times 0.0245) = 25000m$