Is Center of Mass Useful?

A square wire of side length L L and mass M M is centered on the origin in the x y xy plane. A point-particle of mass M M is positioned at ( x , y ) = ( L , 0 ) (x,y) = (L,0) .

What is the magnitude of the gravitational force between the two objects?

Details and assumptions:
1) Everything in standard physical units
2) Gravitational constant G = 6.67 × 1 0 11 G = 6.67 \times 10^{-11}
3) L = 1 L = 1
4) M = 1 0 6 M = 10^6
5) The wire's mass is uniformly distributed over its length


The answer is 80.267.

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1 solution

Otto Bretscher
Nov 27, 2018

G M 2 4 ( 1 / 2 1 / 2 1 / 2 ( 1 / 4 + y 2 ) 3 / 2 d y + 1 / 2 1 / 2 1 / 2 ( 9 / 4 + y 2 ) 3 / 2 d y + 2 1 / 2 1 / 2 1 x ( 1 / 4 + ( 1 x ) 2 ) 3 / 2 d x ) = 66.7 ( 2 2 3 10 ) 80.266 \frac{GM^2}{4}\left(\int_{-1/2}^{1/2}\frac{1/2}{(1/4+y^2)^{3/2}}dy+\int_{-1/2}^{1/2}\frac{1/2}{(9/4+y^2)^{3/2}}dy+2\int_{-1/2}^{1/2}\frac{1-x}{(1/4+(1-x)^2)^{3/2}}dx\right)=66.7\left(\sqrt{2}-\frac{2}{3\sqrt{10}}\right)\approx \boxed{80.266}

With the dimensions of the wire being large relative to the distance of the attracting bodies, naively using the center of mass does not give a good approximation, of course.

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