A student wrote an equation on a blackboard. He then changed a number with a letter. If he wrote ( 2 + 1 ) + ( 2 + 2 ) 2 + ⋯ + ( 2 + a ) a = 2 a + 4 a such that a ∈ N .
If ( 2 + a ) is of odd parity then, is he wrong ?
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I have made little changes in my problem. So please change your solution accordingly.
As the problem is currently written, the LHS could be odd or even.
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It will be always even now. Will edit in some time
Am I misunderstanding the question?
Let a = 1 . a ∈ N and 2 + a is odd.
But 2 + 1 = 2 1 + 4 1
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2 + a = o d d ⇒ a = o d d
Last term of equation is ( 2 + a ) a
As a is o d d → 2 + a = o d d → ( 2 + a ) a = o d d
So, LHS is odd but RHS is even.
So, he definitely has made mistake