Is it a periodic function?

Level 2

y y is a function that satisfies the following y ( x + 1 ) = 1 y ( x ) 1 + y ( x ) y(x+1) = \dfrac{1-y(x)}{1+y(x)}

If you think that y y is a periodic function, find its fundamental period?

5 4 y y is not a periodic function 3 2

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1 solution

Ossama Ismail
May 12, 2020

A function y y is said to be periodic if, for some nonzero constant p p , it is the case that y ( x + p ) = y ( x ) \ \ y(x+p)=y(x)

y ( x + 2 ) = 1 1 y ( x ) 1 + y ( x ) 1 + 1 y ( x ) 1 + y ( x ) = y ( x ) y(x+2) = \dfrac { 1- \dfrac{1-y(x)}{1+y(x)}} {1+ \dfrac {1-y(x)}{1+y(x)}} = y(x)

From the above equation, we can see that y y is a periodic function that repeats its values at regular intervals/periods = 2 =2 .

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