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There are 2.68 × \times 10 18 ^{18} atoms in 1 mg of radium , whose half-life is 1620 years. How many radium atoms will decay from 1 mg pure radium in 3240 years?

3 × 1 0 8 3\times10^8 2.01 × 1 0 18 2.01 \times 10^{18} 3 × 1 0 17 3\times10^{17} 2.02 × 1 0 18 2.02\times10^{18}

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1 solution

Chew-Seong Cheong
May 28, 2016

From 1 mg or 2.68 × 1 0 18 2.68 \times 10^{18} atoms of radium, half ( 1 2 \frac{1}{2} ) of it will decay in a half-life of 1620 years. In 3240 years or another half-life half of the remaining half or ( 1 2 × 1 2 = 1 4 \frac{1}{2}\times \frac{1}{2} = \frac{1}{4} ) will decay, therefore a total of 3 4 × 2.68 × 1 0 18 = 2.01 × 1 0 18 \frac{3}{4} \times 2.68 \times 10^{18} = \boxed{2.01 \times 10^{18}} will decay away.

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