This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
1 solution
It is easy to observe that a=1 ( due to the Limit).
Using condition f(1)=f(2)/2
We get e= 14+6b+2c
Using condition f(1)=f(3)/3
we get e=39+12b+3c
Equating above 2 equations for e, we get -25=6b+c
Now f(i) + f(-i) = 2a-2c+2e
Putting the value of e as 14+6b+2c, we get f(i)+f(-i) = 30+12b+2c
Again putting, 6b+c =-25 in last equation, we get f(i)+f(-i)= 30-50=-20
This implies that k = 20