A Drunkard walking in a narrow lane takes 5 steps forward and 3 steps backward, followed again by 5 steps forward and 3 steps backward, and so on. Each step is 1 m long and requires 1 s. How long the drunkard takes to fall in a pit 13 m away from the start.
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It takes 8 seconds for 2metres if he moves 5 steps forward & 3 steps backward. So, this continues for 4 rounds, i.e, 32s where he reaches 8 metres. And when he takes 5 steps forward, he's in the pit. So it takes 5 more seconds.
So 37 seconds in total.