Pitfall

Logic Level 1

A Drunkard walking in a narrow lane takes 5 steps forward and 3 steps backward, followed again by 5 steps forward and 3 steps backward, and so on. Each step is 1 m long and requires 1 s. How long the drunkard takes to fall in a pit 13 m away from the start.

35 s 40 s 37 s 39 s

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3 solutions

Aditya R Mohan
Jun 15, 2015

It takes 8 seconds for 2metres if he moves 5 steps forward & 3 steps backward. So, this continues for 4 rounds, i.e, 32s where he reaches 8 metres. And when he takes 5 steps forward, he's in the pit. So it takes 5 more seconds.

So 37 seconds in total.

Rajdeep Bharati
Nov 3, 2015

This question is from class 11 Physics NCERT Textbook.

Azadali Jivani
Sep 26, 2015

It cover 2m (ie,5 - 3 = 2) in 8 sec. (ie, 5 + 3 = 8)
............1m......................in 4 sec.
............8m.....................in 8 * 4 = 32 sec.
...........13m (ie. 8 + 5 = 13) in 32 + 5 = 37 sec NOTE. After 13 m it fall in a pit & no chance to move backward


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