is it just limits?

Calculus Level 4

lim n ( 1 n n + 1 + 1 n n + 2 + + 1 n n + n ) \lim_{n \to \infty} \left(\frac 1{\sqrt n \sqrt {n+1}}+\frac 1{\sqrt n \sqrt {n+2}}+\cdots+\frac 1{\sqrt n \sqrt {n+n}}\right)

Find the value of the closed form of the above limit to 2 decimal places.


The answer is 0.83.

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1 solution

Brian Moehring
Feb 2, 2017

Relevant wiki: Riemann Sums

k = 1 n 1 n n + k = k = 1 n 1 1 + k n 1 n n 0 1 1 1 + x d x = 2 1 + x 0 1 = 2 2 2 0.83 \sum_{k=1}^n \frac{1}{\sqrt{n}\sqrt{n+k}} = \sum_{k=1}^n \frac{1}{\sqrt{1+\frac{k}{n}}} \cdot \frac{1}{n} \xrightarrow{n\rightarrow \infty} \int_0^1 \frac{1}{\sqrt{1+x}}\,dx = 2\sqrt{1+x}\Big|_0^1 = 2\sqrt{2} - 2 \approx \boxed{0.83}

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