Is it Linear?

Calculus Level 4

y ′ × ( x 2 y 3 + x y ) = 1 y' \times \big(x^2 y^3 + xy \big) = 1

The general solution of the differential equation above is ____________________ . \text{\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_}.

1 x = 1 − y 2 + c e − y 2 2 \frac{1}{x} = 1 - y^2 + ce^{\frac{-y^2}{2}} 1 x = 2 − y 2 + c e − y 2 2 \frac{1}{x} = 2 - y^2 + ce^{\frac{-y^2}{2}} 2 x = 1 − y 2 + c e − y 2 2 \frac{2}{x} = 1 - y^2 + ce^{\frac{-y^2}{2}} 2 x = 2 − y 2 + c e − y 2 2 \frac{2}{x} = 2 - y^2 + ce^{\frac{-y^2}{2}}

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Vishwak Srinivasan by Vishwak Srinivasan , 24, India

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1 solution

Sorry for the bad hand writing, but writing this solution in latex would have taken a long time on phone.

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