Is it possible to find?

Find the last three digits of 137 6 1376 1376^{1376} .


The answer is 376.

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1 solution

Otto Bretscher
Feb 15, 2016

We have 137 6 1375 ( 11 × 125 + 1 ) 1375 1 ( m o d 125 ) 1376^{1375}\equiv (11\times125+1)^{1375}\equiv1 \pmod{125} so 137 6 1376 1376 376 ( m o d 1000 ) 1376^{1376}\equiv 1376\equiv \boxed{376} \pmod{1000} .

This can be done using CRT too . It becomes bit tedious though...

A Former Brilliant Member - 5 years, 4 months ago

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Yes CRT is (almost) always tedious to apply in computations. I try to avoid it as a computational tool.. but it is useful conceptually!

Otto Bretscher - 5 years, 4 months ago

Very well explained ,indeed. Sir , while crafting this question I found a peculiar property that any number ending with 376 if raised to any power gives a number which also ends with 376.can you please give some explanation for this property?

Sanjeev Gupta - 5 years, 4 months ago

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Yes, that is a great observation! Note that 37 6 2 376 ( m o d 1000 ) 376^2\equiv 376 \pmod{1000} since the congruency reduces to 1 1 ( m o d 125 ) 1\equiv1 \pmod{125} and 0 0 ( m o d 8 ) 0\equiv 0\pmod{8} . Now we have 37 6 n 376 ( m o d 1000 ) 376^n\equiv 376 \pmod{1000} by induction.

Otto Bretscher - 5 years, 4 months ago

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Thank you sir.A very nice explanation.Upvoted!

Sanjeev Gupta - 5 years, 3 months ago

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