How many degrees are there in the angle between the hour and minute hands of a clock when the time is a quarter past three?
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This correctly finds a sort of "reference angle", but generally we require the "angle between two vectors" to be between 0 and 180 degrees, and that answer can give angles of -324.5 and 330...
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Yeah, so it is better to take its absolute value and keep the range [ 0 , 1 8 0 ] . Thanks. I've edited my solution.
Simple, the hour hand moves 3 0 ∘ in 6 0 mins. ie, it moves at a rate of 6 0 3 0 = 0 . 5 ∘ / m i n
At quarter past three the minute hand is points directly at 3 while hour hand has moved 0 . 5 × 1 5 = 7 . 5 ∘
Hence, the angle between hour and minute hand is ( 9 0 ∘ + 7 . 5 ∘ ) − 9 0 ∘ = 7 . 5 ∘
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Actually, I would like to generalize the formula for finding the angle between the hour hand and minute hand in degrees.
Consider a time representation h : m where h is the no. of complete hours passed and m the exact and precise minutes elapsed. Then:
The exact hours elapsed = h + 6 0 m Starting from 1 2 , part of the clock swiped by the hour hand = 1 2 ( h + 6 0 m )
Angle (in degrees) between 1 2 and the hour hand = 1 2 ( h + 6 0 m ) ⋅ 3 6 0 = 3 0 h + 2 m
Similarly, starting from 12, part of the clock swiped by the minute hand = 6 0 m
Angle (in degrees) between 1 2 and the minute hand = 6 0 m ⋅ 3 6 0 = 6 m
Clearly then, the angle between the hour hand and minute hand will be = ∣ 3 0 h + 2 m − 6 m ∣ = ∣ 3 0 h − 2 1 1 m ∣
Note: One must notice that when h = 1 2 , one must take h = 0 since 1 2 has been taken as the frame of reference here. (12 is the starting point)