( x + 1 ) 3 + ( x + 2 ) 3 + ( x + 3 ) 3 + ( x + 4 ) 3 = ( x + 1 0 ) 3
Find the least rational solution to the equation above.
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@Anish Harsha The R.H.S term should be ( x + 1 0 ) 3 not ( x + 5 ) 3 .
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Let's take x = t + 1 0 .
If we substitute it in the equation, we reduce our equation to
3 t ( t 2 + 4 0 t + 2 3 0 ) = 0
Since the equation t 2 + 4 0 t − 2 3 0 = 0 has no rational solutions, we must have t = 0 .
Thus, our equation has only one and least solution in positive integers namely x = 1 0 .
So, the only solution is 1 0 .