Is the following true? (2)

Using any math symbols, signs, or operations, is it true that we can complete the following to make the equation valid? You may not use any additional numbers. Please provide a solution.

0 0 0 = 6 0 \ 0 \ 0 = 6

1 1 1 = 6 1 \ 1 \ 1= 6

2 2 2 = 6 2 \ 2 \ 2 = 6

3 3 3 = 6 3 \ 3 \ 3 = 6

4 4 4 = 6 4 \ 4 \ 4 = 6

5 5 5 = 6 5\ 5 \ 5 = 6

6 6 6 = 6 6\ 6 \ 6 = 6

7 7 7 = 6 7\ 7 \ 7= 6

8 8 8 = 6 8 \ 8 \ 8 = 6

9 9 9 = 6 9 \ 9 \ 9 = 6

False True

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1 solution

Hana Wehbi
Jan 21, 2018

Here is one solution:

( 0 ! + 0 ! + 0 ! ) ! = 6 (0!+0!+0!)!= 6

( 1 + 1 + 1 ) ! = 6 (1+1+1)! = 6

2 + 2 + 2 = 6 2+2+2= 6

( 3 × 3 ) 3 = 6 (3\times 3) - 3 =6

4 + 4 + 4 = 6 \sqrt{4}+\sqrt{4}+\sqrt{4} = 6

( 5 / 5 ) + 5 = 6 (5/5) +5 = 6

6 + 6 6 = 6 6 + 6 - 6 = 6

7 ( 7 / 7 ) = 6 7 - (7/7) = 6

( ( 8 / 8 ) + 8 ) ! = 6 (\sqrt{(8/8)+8})! =6

9 × 9 9 = 6 \sqrt{9}\times \sqrt{9} - \sqrt{9} = 6

Clever prob, Hana!

tom engelsman - 3 years, 4 months ago

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Thanks for the support.

Hana Wehbi - 3 years, 4 months ago

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