The natural length of the spring is . One end of the spring is attached to a fixed platform (indicated in red) while the other is attached to a point mass constrained to move on a horizontal rail. The mass is given a small initial displacement of to the right from its equilibrium position and is then released. The system is placed in a gravity-free environment.
The following claim is made: " The resulting motion of the system is not simple harmonic".
Is the claim true or false?
Note:
This problem is not original.
Bonus: If your answer is false, compute the natural frequency of small oscillations.
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The Lagrangian for this system is:
L = 2 1 m x ˙ 2 − 2 1 k ( a 2 + x 2 − a ) 2
The equation of motion is:
d t d ∂ x ˙ ∂ L = ∂ x ∂ L
Evaluating results in:
m x ¨ = − k x ( 1 − a 2 + x 2 a )
Taylor series approximation for small x :
a 2 + x 2 ≈ a + 2 a x 2
Plugging into the previous expression and simplifying results in:
m x ¨ ≈ − k x ( 2 a 2 + x 2 x 2 ) ≈ − 2 a 2 k x 3
Using small- x approximations, the double-dot term is proportional to the cube of the displacement. Thus, the expression does not represent SHM.