Is the value 11
Algebra
Level
3
Suppose f (x) is a polynomial of degree 5 with leading coefficient 2009. It is given that f (1)=1, f (2)=3, f(3)=5 f (4)=7, f (5)=9. Find the value of f (6).
The answer is 241091.
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1 solution
That polynomial is 2009(x-1)(x-2)(x-3)(x-4)(x-5)+2x-1