IS TRIGONOMETRY SIMPLE ENOUGH???????????

Geometry Level pending

Find the minimum value of the function


The answer is 13.37.

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1 solution

Akhil Ayyadevara
May 6, 2014

clearly\quad the\quad function\quad is\quad in\quad the\quad form\quad of\quad { ({ x } { 1 }-{ x } { 2 }) }^{ 2 }+{ ({ y } { 1 }-{ y } { 2 }) }^{ 2 }\quad ......\ where\quad { x } { 1 }=4\cot { x } \quad and\quad { y } { 1 }=4tanx......\quad and\quad { x } { 2 }=2cosx\quad and\quad { y } { 2 }=2sinx\ \ { x } { 1 }{ y } { 1 }=16.....\Longrightarrow ({ x } { 1 },{ y } { 1 })\quad is\quad a\quad point\quad on\quad hyperbola\quad xy=16....\ \ similarly\quad ({ x } { 2 },{ y } { 2 })\quad is\quad a\quad point\quad on\quad the\quad circle\quad { x }^{ 2 }+{ y }^{ 2 }=4.....\ \ Now\quad tofind\quad the\quad minimum\quad value\quad of\quad the\quad function\quad we\quad need\quad to\quad find\quad the\quad shortest\quad distance\quad \ between\quad the\quad two\quad curves\quad xy=16\quad and\quad { x }^{ 2 }+{ y }^{ 2 }=4..............\quad which\quad lies\quad along\quad common\quad normal............\ the\quad required\quad answer\quad is\quad square\quad of\quad the\quad shortest\quad distance......

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