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Calculus Level pending

$\large \lim_{x\to0} \left \lfloor - \dfrac x{\sin x} \right \rfloor = \, ?$

[ . ] denotes G.I.F.

-1

-2

2

1

1 solution

Tanmay Sinha
May 24, 2016

The given function is even. So its graph would be symmetric about y-axis. Hence , the limit would exist .

By graph , we know that x > sinx ;

x/sinx > 1 ;

-x/sinx < -1 ;

[-x/sinx] = -2