ISI entrance 2014 problem


The answer is 4.

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1 solution

Ankan Dutta
May 1, 2016

For every Pythagorean triplet 6 divides 'abc' so 3 divides 'abc'. As 3 divides c. So a^2 + b^2 is congruent to 0 in 9 modulo. a^2 can be congruent to 0, 1, 4 only... on 9 modulo. Similarly b^2. So a^2 +b^2 congruent to 0, 2, 1, 5, 4, -1. But this has to be 0.. so only combination is 3 divide a n b respectively. So 27 divides 'abc' and thus 81 divides 'abc' being a Pythagorean triplet.

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