THE NUMBER OF DISTINCT REAL ROOTS OF THE EQUATION (X+1/x)^2-5(x+1/x)+6=0 IS
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let z=x+1/x
then the eqn. is z^2-5z+6=0 there the solutions are z = 2 or 3 x+1/x=2 gives one solitions. x+1/x=3 gives 2 solutions Total no. of solutions are 3.