identical coins each with probability of coming Heads are tossed simultaneously. If and the probability of Heads coming on coins is equal to that of Heads coming on coins, then the value of can be expressed as .
Find the value of .
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Probability of getting 5 0 heads= ( 5 0 1 0 0 ) P 5 0 ( 1 − P ) 5 0
Probability of getting 5 1 heads= ( 5 1 1 0 0 ) P 5 1 ( 1 − P ) 4 9
Equating both expressions,
1 − x x = ( 5 1 1 0 0 ) ( 5 0 1 0 0 ) = 5 0 5 1 ⇒ x = 1 0 1 5 1
a = 5 1 , b = 1 0 1 ⇒ a + b = 1 5 2