Isn't it infinity?

Calculus Level 3

How many functions are there such that f ( x ) > 0 f''(x)>0 for every x > 0 x>0 , f ( 1 ) = 5 f(1)=-5 and f ( 2 ) = 11 f(2)=-11 and f(0)=0 ? If the number of functions is n n , then submit your answer as n ! + n 1 n!+n-1 .

Notation: f ( x ) f''(x) means second derivative of f ( x ) f(x) .


The answer is 0.

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1 solution

Devansh Shringi
Jul 21, 2016

This is a problem i made from a rather very easy problem into a typical one . Consider a function g(x)= f ( x ) x \frac{f(x)}{x} g'(x)= x f ( x ) f ( x ) x x \frac{xf'(x)-f(x)}{x*x} and consider h(x)=xf'(x)-f(x) . h(0)=0 and therefore g'(x)=0 . also h'(x)=x*f''(x) . For x>0 h'(x)>0 . So h(x) is increasing for x>0 . and h(0)=0 . Therefore h(x)>0 for x>0 . Since denominator of g'(x) is positive g'(x) is greater than 0 . therefore g(x) is increasing !!! . but the above data g(1)=-5 and g(2)=-5.5 i.e. g(1)>g(2) . which is not possible as g(x) is increasing . therefore there cannot be such a function .

What about this

f(x)= x 2 9 x + 3 x^{2} -9x + 3

It satisfies f''(x)=2>0 and f(1)-5 and f(2)=-11

Kushal Bose - 4 years, 10 months ago

Bro u forgot f(0)=0 also

devansh shringi - 4 years, 10 months ago

Initially you have not stated that.

You have edited that after my comment

Bcoz u forgot to use latex

Kushal Bose - 4 years, 10 months ago

i didn't add latex it automatically added to others and not f(0) i don't know why

devansh shringi - 4 years, 10 months ago

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