Isopropanol Reaction Scheme

Chemistry Level 3

Follow the reaction scheme for isopropanol shown above. For product E E , choose the best description from each list. List 1: Substituent Level 1 : P r i m a r y : 1 2 S e c o n d a r y : 2 3 T e r t i a r y : 3 4 A l p h a : α 5 B e t a : β \text{List 1: Substituent Level} \\ \boxed{1}:Primary:1^{\circ} \\ \boxed{2}Secondary:2^{\circ} \\ \boxed{3}Tertiary:3^{\circ} \\ \boxed{4}Alpha:\alpha \\ \boxed{5}Beta:\beta List 2: Substituent Type 1 : A l k o x i d e 2 : A l c o h o l 3 : E p o x i d e 4 : C a r b o x y l i c A c i d 5 : E t h e r \text{List 2: Substituent Type} \\ \boxed{1}:Alkoxide \\ \boxed{2}:Alcohol \\ \boxed{3}:Epoxide \\ \boxed{4}:Carboxylic Acid \\ \boxed{5}:Ether Your answer will be the combo of the boxed digits associated with the correct labels in both lists; for example, if product E E is a tertiary carboxylic acid, then your answer will be 34 34 Suggested wiki: Grignard Reagents


David's Organic Chemistry Set

David's Physical Chemistry Set


The answer is 21.

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1 solution

David Hontz
Jun 18, 2016

Relevant wiki: Grignard Reagent

Product E is a Secondary ( 2 ) Alkoxide ( 1 ) Thus the answer is 21 \text{Product E is a Secondary (}\boxed{2} \text{) Alkoxide (} \boxed{1} \text{)} \\ \text{Thus the answer is } \boxed{21} Note: Product D D is a grignard reagent and product B B is an epoxide. When mixed, the grignard will favor attacking the least substituted carbon in the epoxide ring. For this reason, product E E will open up to form a secondary alkoxide.

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AYUSH JAIN - 4 years, 10 months ago

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