It can be simple if you know who is Fermat

True or False?

\quad The number 2744 can be expressed as the sum of two positive perfect cubes .

Yes It is not possible to say No

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1 solution

The first step is to get the prime factors of this number:

2744 ÷ 2 = 1372 2744 \div 2 = 1372

1372 ÷ 2 = 686 1372 \div 2 = 686

686 ÷ 2 = 343 686 \div 2 = 343

343 ÷ 7 = 49 343 \div 7 = 49

49 ÷ 7 = 7 49 \div 7 = 7

7 ÷ 7 = 1 7\div 7 = 1

Then, 2744 = 2 3 7 3 2744=2^3 \cdot 7^3 , which means that it's a perfect cube.

By Fermat's Last Theorem, there is no perfect cube that can be expressed by the sum of other perfect cubes. In general:

a x + b x = c x a^x + b^x = c^x have no positive integer solution, when x > 2 x>2 .

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