It is easy

Algebra Level 1

n = 4 x + 12 x + 3 n=\dfrac{4x+12}{x+3} Find the value of n n , if x = 201720172017 x=201720172017 .


The answer is 4.

Áron Bán-Szabó by Áron Bán-Szabó , 17, Hungary

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3 solutions

Áron Bán-Szabó
Aug 27, 2017

4 x + 12 x + 3 = 4 × ( x + 3 ) x + 3 = 4 × x + 3 x + 3 Note that x + 3 ≠ 0 = 4 \begin{aligned} \dfrac{4x+12}{x+3} & = \dfrac{4\times (x+3)}{x+3} \\ & = 4\times \dfrac{x+3}{x+3} & \text{Note that} \ x+3\neq0 \\ & = \boxed{4} \end{aligned}

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Mohammad Khaza
Aug 30, 2017

take common(4).then the numerator and the denominator will be same.

1 Helpful 0 Interesting 0 Brilliant 0 Confused

A typo. Nominator?

Munem Shahriar - 3 years, 9 months ago

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spelling mistake.that is..numerator

Mohammad Khaza - 3 years, 9 months ago

= 4 x + 12 x + 3 = 4 ( x + 3 ) x + 3 = 4 =\frac { 4x+12 }{ x+3 } \\ =\frac { 4(x+3) }{ x+3 } \\ =4

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