It is Geometry, isn't it?

Geometry Level 3

5 points are on the coordinate of plane, no three of which are collinear. How many polygons can be drawn with these points as vertices?


The answer is 16.

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1 solution

Julia Lange
Jun 5, 2015

Having 5 points, where no three are collinear we can make a pentagon, tetragon or a triangle. There is only 1 1 possibility to make a pentagon, choosing all the available points. To make a tetragon we have to pick 4 points, we can do this in 5 different ways:

( 5 4 ) = 5 ! 4 ! ( 5 4 ) ! = 5 \left( \begin{matrix} 5 \\ 4 \end{matrix} \right) =\frac { 5! }{ 4!(5-4)! } =5

There are 10 possibilities to make a triangle, picking 3 points:

( 5 3 ) = 5 ! 3 ! ( 5 2 ) ! = 5 ! 3 ! 2 ! = 4 5 2 = 10 \left( \begin{matrix} 5 \\ 3 \end{matrix} \right) =\frac { 5! }{ 3!(5-2)! } =\frac{5!}{3!2!}=\frac{4\cdot 5}{2}=10

So we can make:

1 + 5 + 10 = 16 1+5+10 =16 polygons

I did the same ¨ \ddot \smile

Akshat Sharda - 5 years, 9 months ago

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But ain't it weird that it is listed under Geometry?

Aditya Agarwal - 5 years, 5 months ago

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Yes ! You are right !!

Akshat Sharda - 5 years, 5 months ago

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