What is the largest even integer that cannot be written as the sum of two odd composite positive integers?
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Firstly, we will show that 38 cannot be written as a sum of two composite odd numbers.
For this, it is enough to show that the bigger (or one of the equal numbers, 19 in this case, which means that both are primes) number b cannot be composite.
Since s is the smaller number (when b is the bigger number), therefore
s + s ≤ s + b = 3 8 ⟺ 2 s ≤ 3 8 ⟺ s ≤ 1 9
The composite odd numbers in the 0 < s ≤ 19 interval are:
9 : 9 + 29 = 38 , 29 is a prime, therefore not a composite number
15 : 15 + 23 = 38 , 23 is a prime, therefore not a composite number.
Hence, 38 cannot be written as a sum of two composite positive odd numbers.
Now, we will show that all N > 38 (even) numbers can be written as a sum of two odd positive integers.
Let's have a look at the following cases:
a) N = 3 k , k ∈ Z + , k ≥ 1 3 :
With the choice of s = 9 (composite: 9 = 3 × 3; the smallest positive odd composite integer (divisible by 3)), we have
N = s + b = 3k = 9 + (3k - 9) = 9 + 3(k - 3)
b = 3(k - 3) , which is composite, as it has at least two factors:
3 and (k - 3) ≥ 10 > 1.
b) N = 3 k + 1 , k ∈ Z + , k ≥ 1 3 :
With the choice of n 1 = 2 5 (composite: 25 = 5 × 5;
25 is the smallest positive odd composite integer (giving a remainder of 1 when divided by 3)), we have:
N = n 1 + n 2 = 3 k + 1 = 2 5 + ( 3 k − 2 4 ) = 6 + 3 ( k − 8 )
n 2 = 3 ( k − 8 ) , which is composite, too, as it has at least two factors:
3 and (k - 8) ≥ 5 > 1.
c) N = 3 k + 2 , k ∈ Z + , k ≥ 1 3 :
With the choice of n 1 = 3 5 (composite: 35 = 5 × 7 ;
35 is the smallest positive odd composite integer (giving a remainder of 2 when divided by 3)), we have: } )
N = n 1 + n 2 = 3 k + 2 = 3 5 + ( 3 k − 3 3 ) = 6 + 3 ( k − 1 1 )
n 2 = 3 ( k − 1 1 ) , which is composite, too, as it has at least two factors:
3 and (k - 11) ≥ 2 > 1.
Therefore, the largest even integer that cannot be written as the sum of two odd composite positive integers is:
3 8