The figure above shows a right triangle inscribed in a circle of diameter 58. If each side lengths of the triangle is an integer, then what is the area of the green region?
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Since this is a right angled triangle with all the points touching the circle, by Thales' theorem we know that the diameter is the hypotenuse of the triangle. Since it's mentioned that both the numbers are integers, using Pythagorus theorem we can figure out both the sides
a 2 + b 2 = 5 8 2 which is 3364
now we need 2 integers whose squares sum up to 3364
Dividing 3364 by 2 gives 1682 (since there are 2 sides)
1 6 8 2 ~ 41, that tells us both the integers are close to 41, they are 40 & 42
The sides of the triangle are 40-42-58 and the area of the triangle is 840
Hence the answer is 841 π - 840
Note to the publisher : It looks like a play button not pause :p