Which of the following statements is true?
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Statement: There are 3 ways to rearrange the word THREE.
Reply: Fasle . It should be 2 ! 5 ! = 6 0 ways.
Statement: There are 4 ways to rearrange the word FOUR.
Reply: Fasle . It should be 4 ! = 2 4 ways.
Statement: There are 5 ways to rearrange the word FIVE.
Reply: Fasle . It should be 4 ! = 2 4 ways.
Statement: There are 6 ways to rearrange the word SIX.
Reply: True . There are 3 ! = 6 ways.
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Relevant wiki: Permutations without Repetition - Basic
There are 3! = 6 ways to rearrange the 3 letters of the word "six".
(While there are 4! = 24 ways to rearrange the 4 letters of the words "four" and "five" and 5! ÷ 2! = 60 ways to rearrange the 5 letters (of which the 2 "e"s are identical) of the word "three".)