has a value such that the closest integer to it is . If the actual value of it is where the fraction is in the lowest terms and is prime, find the value of ?
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One definition of π is: π 1 = 9 8 0 1 2 2 n = 0 ∑ ∞ ( n ! ) 4 3 9 6 4 n ( 4 n ) ! ( 1 1 0 3 + 2 6 3 9 0 n ) So with some simple algebra, we can get: n = 0 ∑ ∞ ( n ! ) 4 3 9 6 4 n ( 4 n ) ! ( 1 1 0 3 + 2 6 3 9 0 n ) = π × 2 2 9 8 0 1 which makes the answer 1 1 0 3 + 9 8 0 1 + 2 + 2 = 1 0 9 0 8