It Works Both Ways?

The largest positive integer that divides the numbers 16 and 20 is 4.

What is the smallest value of the positive integer n n such that the largest positive integer that divides the numbers n n ,16, and 20 is also 4?

2 4 8 16

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1 solution

We have to find the smallest positive integer that is divisible by 4 i.e, 4.

Why must it be divisible by 4 only? Why isn't there any other constraints?

Pi Han Goh - 5 years ago

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H.C.F is 4. As H.C.F remains same, the new number must be a multiple of 4.

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