It's 2014!

Level pending

Let f be a function where f(a+b) = f(ab).

If f(2) = 2, find f(2014).

1 solution

Alex Li
May 8, 2015

Note that , by substituting $a=0$ , $f(b)=f(0)$ for all real numbers $b$ , so $f$ is a constant function. Thus, $f(2014)=\boxed{2}$ .