It's a milky day

Algebra Level 3

A dishonest milkman has one bucket of milk of 80% purity.He has another bucket of milk of 60% purity.How much milk from first bucket should he mix to supply 20 liters of milk of 75% purity ?


The answer is 15.

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1 solution

Tejas Ramdas
Sep 27, 2015

Intuitively, one can observe that 75 lies three-fourths of the way from 60 to 80, therefore, three-fourths of the final quantity should be 80% milk and the remaining 60% milk.

We can use simultaneous equations to solve this problem.

In the first bucket, there are 0.8 l 0.8 l of pure milk in 1 l 1l of milk. In the second bucket, there are 0.6 l 0.6l of pure milk in 1 l 1l of milk.

Certain volumes of milk from each of the two buckets are mixed in order to obtain 20 l 20l milk of 75 % 75\% purity.

Therefore , x + y = 20 x+y=20 0.8 x + 0.6 y = 0.75 × 20 0.8x+0.6y=0.75\times 20

Solving which gives x x as 15, which is the answer.

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