It's a Triangle!

Using the sine rule, $a=6\sin A \\b=6\sin B\\c=6\sin C$

The area of the triangle is given by $\mbox{Area}=\frac{1}{2}ab\sin C=\frac{1}{2}ab\cdot\frac{c}{6}=\frac{1}{12}abc=10$

The area of a triangle can be written as $\frac{abc}{4R}$ , where $abc$ is the product of the length of the sides of the triangle, and $R$ is the circumradius of the triangle. Therefore, the area of this triangle is: $\frac{120}{4 \times 3}$ $= \frac{120}{12}$ $= \boxed{10}$

a × b × c = 120 c / sin (A) = 2r = 6 ---> c = 6sin (A) Hence : a × b × 6sin (A) = 120 ---> a×b×sin (A) = 20 [a×b×sin (A)] / 2 = 10 ---> the area of a triangle

Sorry for not making it look fancy :P still learning.