Find the smallest positive integer such that, if you put the number 2 on the left and the number 1 on the right, the new number is equal to .
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we have
33n=10n+1+2*10^k
23n=2 * 10^k+1
So we start by looking for the smallest integer k that results in 2*10^k+1 being divisible by 23. Simple trial and error quickly gives this to be k=3 which gives n=87.