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Geometry Level 3

Let O = ( 0 , 0 ) , P = ( 3 , 4 ) , Q = ( 6 , 0 ) O=(0,0), P=(3,4), Q=(6,0) be the vertices of triangle O P Q . OPQ. Point R R inside the triangle is such that triangles O P R , P Q R , O Q R OPR, PQR, OQR are of equal area.

The product of the coordinates of R R is __________ . \text{\_\_\_\_\_\_\_\_\_\_}.


The answer is 4.

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4 solutions

Ram Gautam
Jan 6, 2015
  • The point R will be the centroid of the triangle due to the given condition

Coordinates of R ( 0 + 6 + 3 3 ; 0 + 4 + 0 3 ) R\in \left( \frac { 0+6+3 }{ 3 } ;\frac { 0+4+0 }{ 3 } \right)

3 × 4 3 = 4 3\times \frac { 4 }{ 3 } =4\quad

If instead, the point was asked outside the triangle then R=_(9,4) I first wrote 36 and then read it was inside!!

Ninad Jadkar - 6 years, 5 months ago
Paola Ramírez
Jan 7, 2015

The point R R is the centroid of the triangle, also O P Q \triangle OPQ is isosceles, consequently, the centroid of the triangle has coordinate x = 3 x=3 . To find y y coordinate find the distance between P y P_y and 0 0 that is equal 4 4 , divides by 3 3 and sum 4 3 + 0 \frac{4}{3}+0

R ( 3 , 4 3 ) \boxed{R(3,\frac{4}{3})} and its product is 4 4

Yup, Cool Way!

Ram Gautam - 6 years, 5 months ago
Divyanshu Mehta
Jan 17, 2015

Sins the area of all the triangles are same this means that R is the centroid of the triangle. Centroid of the triangle on solving will come out as (3,4/3) and the product will be 3*4/3 = 4units

Guru Prasaadh
Jan 8, 2015

how can this be a level 3 problem

Even I am surprised! xD

Ram Gautam - 6 years, 5 months ago

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