Let O = ( 0 , 0 ) , P = ( 3 , 4 ) , Q = ( 6 , 0 ) be the vertices of triangle O P Q . Point R inside the triangle is such that triangles O P R , P Q R , O Q R are of equal area.
The product of the coordinates of R is __________ .
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If instead, the point was asked outside the triangle then R=_(9,4) I first wrote 36 and then read it was inside!!
The point R is the centroid of the triangle, also △ O P Q is isosceles, consequently, the centroid of the triangle has coordinate x = 3 . To find y coordinate find the distance between P y and 0 that is equal 4 , divides by 3 and sum 3 4 + 0
R ( 3 , 3 4 ) and its product is 4
Yup, Cool Way!
Sins the area of all the triangles are same this means that R is the centroid of the triangle. Centroid of the triangle on solving will come out as (3,4/3) and the product will be 3*4/3 = 4units
how can this be a level 3 problem
Even I am surprised! xD
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Coordinates of R ∈ ( 3 0 + 6 + 3 ; 3 0 + 4 + 0 )
3 × 3 4 = 4