In the figure shown, two identical circles of radius 12 cm each are drawn with centres C and C' with AB and BD being their respective tangents at A and D.If BE is their common tangent and AB perpendicular to BD, then find the length of BD.
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Look The figure
Triangle OHO' is right angled with angles 45, 45 and 90
So ratio of sides is 1 : 1 : 2
The length of line OO' = radius of the circle × 2
So OO' = 12 × 2 = 24
Then OH = O'H = 2 2 4
If the point where two lines join is considered as M Then CHBM is a square
So MB = BH
BH = 2 2 4 + 1 2 = 2 8 . 9 7 0