Distinct integers

What is the smallest possible positive value of

5 7 m + 4 5 n = ? 57^{m} + 45^{n} = ?

where m m and n n are distinct positive integers.


The answer is 2082.

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1 solution

Sathvik Acharya
Aug 30, 2017

To minimize the value of 5 7 m + 4 5 n 57^m+45^n we need to minimize both m , n m,n . The minimum value occurs when m = n = 1 m=n=1 , but since m , n m,n have to be distinct we go to the next one that is m = 1 , n = 2 m=1,n=2 which is better than m = 2 , n = 1 m=2,n=1 . Therefore the minimum possible value of 5 7 m + 4 5 n 57^m+45^n is 5 7 1 + 4 5 2 = 2082 57^1+45^2=\boxed{2082} .

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