It's easy

Let first number be $a$

Step 1 : $a+1$

Step 2 : $2(a+1)=2a+2$

Step 3 : $2a+2+3=2a+5$

Step 4 : $5(2a+5)=10a+25$

Let next added number be $b$

Step 5 : $10a+25+b=79\Rightarrow 10a+b=54$

But $10a+b$ is same as 2-digit number $\overline{ab}$

So, $\overline{ab}=54$ or,

$\boxed{a=5}$ and $\boxed{b=4}$

Let the first number be x and the second be y. Then following the operations given in the problem, we get 5[2(x+1)+3]+y=79 or 10x+y+25=79 or 10x+y=79-25=54. x is the ten 's place digit, which is 5 and y is the unit's place digit, which is 4.