if a right angled triangle has side lengths a,b and c such that c is hypotenuse and c = 2 2 a b find the smallest angle of the triangle?
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√(a²+b²)=√(ab), a²+b²=ab, and a,b>0, therefore a,b=1. It is a right isosceles triangle that has angles of 45°, 45°, and 90°.
Both a , b need not be 1 . We have a = b .
Here's why. From a 2 + b 2 = 2 a b , we get a nice factorization, giving us a = b . You dropped a 2.
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c=sqrt 2ab or c^2=(sqrt 2ab)^2 or c^2=2ab or a^2+b^2=2ab or a^2-2ab+b^2=0 or (a-b)^2=0 or (a-b)=0 or a=b.So its an isosceles right triangle.That means angles are 90,45,45.So the smallest angle is/are 45