its easy

Algebra Level 1

If the mean (average) of five consecutive integers is 21, the smallest of the five integers is


The answer is 19.

Pranav Sadhu by pranav sadhu , 20, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Vishal S
Jan 1, 2015

Let the numbers be x

Mean of 1st 5 consecutive integers is 21 =>x+x+1+x+2+x+3+x+4/5 =21

=>5x+10 / 5=21

=>5x+10=105

=>5x=95

=>x=19

therefore the smallest of the five consecutive integer is x i.e 19

0 Helpful 0 Interesting 0 Brilliant 0 Confused

Shouldn't it be 6x??

Vaibhav Kandwal - 6 years, 5 months ago

Log in to reply

there are five consecutive integers

let the smallest integer be x

the following integers are x+1, x+2, x+3, x+4

to add the five integers, it's 5x+10

Sophia P - 6 years, 5 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...