It's easy, isn't it?
Three groups of people having the same number of persons in each group entered three rooms of a house for night stay. They observed that there were different number of cotts in the rooms. The first group took as many cotts from the second room as they had in their room. The second group took as many cotts from the third room as they had initially. After this, all the rooms have the same number of cotts and the same as the number of people in each group. What is the minimum number of people in each group?
The answer is 4.
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1 solution
Let the first room had x cotts, the second had y cotts and the third had z cotts. Then by the given condition of the problem, 2x=2y-x=z-y or x:y:z=2:3:7. Therefore the minimum value of x, y, z are 2,3,7 respectively. Hence the number of people in each group is 2x=4