It's gonna be a good year.

Suppose $x^2= -y \mod{625}$ has integer solutions for $x$ where $y > 0$ . Let the sum of all possible $y \mod{10}$ be $A$ . Let the sum of the first 40 solutions for $y$ (in order from least to greatest) be $B$ . Let the maximum number of possible solutions of $x$ for a specified $y$ be $C$ .

Find $A+B+C-7$ .