Gravity Effectively Isn't Constant

Consider a spherical planet with radius R R , that is rotating with angular velocity ω \omega about it's axis. The lattitude x x of a point P P that is a height of h h away from the equator, is denoted as x = h R x = \frac{h}{R} . Suppose that the acceleration due to gravity at the North pole is g g , then what is the effective acceleration ar point P P in terms of the latitude x x ?

  • T cos x T \cos x is the Centrifugal force along the tangent for rotation.
g 2 ω 2 R cos 2 x g- 2 \omega^2 R \cos^2 x g g g m v 2 R cos x g - \frac{mv^2}R \cos x g ω 2 R cos x g- \omega^2 R \cos x g ω 2 R cos 2 x g- \omega^2 R \cos^2 x

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1 solution

Azmi Prottoy
May 8, 2016

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